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11-x=3x-5(2x-1)
We move all terms to the left:
11-x-(3x-5(2x-1))=0
We add all the numbers together, and all the variables
-1x-(3x-5(2x-1))+11=0
We calculate terms in parentheses: -(3x-5(2x-1)), so:We get rid of parentheses
3x-5(2x-1)
We multiply parentheses
3x-10x+5
We add all the numbers together, and all the variables
-7x+5
Back to the equation:
-(-7x+5)
-1x+7x-5+11=0
We add all the numbers together, and all the variables
6x+6=0
We move all terms containing x to the left, all other terms to the right
6x=-6
x=-6/6
x=-1
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