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11.50/5x+2.44x=1089.08
We move all terms to the left:
11.50/5x+2.44x-(1089.08)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2.44x+11.50/5x-1089.08=0
We multiply all the terms by the denominator
(2.44x)*5x-(1089.08)*5x+11.50=0
We add all the numbers together, and all the variables
(+2.44x)*5x-(1089.08)*5x+11.50=0
We add all the numbers together, and all the variables
(+2.44x)*5x-(1089.08)*5x+11.5=0
We multiply parentheses
10x^2-5445.4x+11.5=0
a = 10; b = -5445.4; c = +11.5;
Δ = b2-4ac
Δ = -5445.42-4·10·11.5
Δ = 29651921.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5445.4)-\sqrt{29651921.16}}{2*10}=\frac{5445.4-\sqrt{29651921.16}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5445.4)+\sqrt{29651921.16}}{2*10}=\frac{5445.4+\sqrt{29651921.16}}{20} $
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