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11.5x^2=23
We move all terms to the left:
11.5x^2-(23)=0
a = 11.5; b = 0; c = -23;
Δ = b2-4ac
Δ = 02-4·11.5·(-23)
Δ = 1058
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1058}=\sqrt{529*2}=\sqrt{529}*\sqrt{2}=23\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-23\sqrt{2}}{2*11.5}=\frac{0-23\sqrt{2}}{23} =-\frac{23\sqrt{2}}{23} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+23\sqrt{2}}{2*11.5}=\frac{0+23\sqrt{2}}{23} =\frac{23\sqrt{2}}{23} =\sqrt{2} $
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