If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(11/12)*(x-(5*y)-(3*z)) = 0
(11/12)*(x-5*y-3*z) = 0
11/12*(x-5*y-3*z) = 0
( 11/12 )
11/12 = 0
x belongs to the empty set
( x-5*y-3*z )
x-5*y-3*z = 0 // + -5*y-3*z
x = -(-5*y-3*z)
x = -(-5*y-3*z)
| 3x+3-3=66-3 | | 3y/4=5/3 | | 7.06/.37=20x | | logx=3.78 | | 4(2x+6)=64 | | 7.06/.37x=20 | | 2m-(-m)+n= | | 23+5x=77 | | 18x+37=7.06 | | 18x+.37=7.06 | | x+15-3=18 | | 20x+.37=7.06 | | 3x-12/5=6 | | 2(-7x+10)=-50 | | -14x=-60 | | 2x(3x-1)-x(2x-3)= | | 7/3x-1=-3/4x-7/4 | | [x+7]=20 | | 250x=50 | | 265x=50 | | 30x+28.4=31.4 | | -7/5x-2/3=5x-3/5 | | 260x=50 | | -75x-2/5=5x-3/5 | | 0.1x+3.7=12.4 | | (3/5)(3/5)(25) | | 1.7+0.5x=3.9 | | 2a(6y+4)=13 | | b-32=-45 | | (2x)2(4x)4(8x)6= | | 2x+1.8=3.9 | | 2+4(-8)= |