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11/12k=33k=
We move all terms to the left:
11/12k-(33k)=0
Domain of the equation: 12k!=0We add all the numbers together, and all the variables
k!=0/12
k!=0
k∈R
-33k+11/12k=0
We multiply all the terms by the denominator
-33k*12k+11=0
Wy multiply elements
-396k^2+11=0
a = -396; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·(-396)·11
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*-396}=\frac{-132}{-792} =1/6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*-396}=\frac{132}{-792} =-1/6 $
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