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11/12n-5/6n=9-5
We move all terms to the left:
11/12n-5/6n-(9-5)=0
Domain of the equation: 12n!=0
n!=0/12
n!=0
n∈R
Domain of the equation: 6n!=0We add all the numbers together, and all the variables
n!=0/6
n!=0
n∈R
11/12n-5/6n-4=0
We calculate fractions
66n/72n^2+(-60n)/72n^2-4=0
We multiply all the terms by the denominator
66n+(-60n)-4*72n^2=0
Wy multiply elements
-288n^2+66n+(-60n)=0
We get rid of parentheses
-288n^2+66n-60n=0
We add all the numbers together, and all the variables
-288n^2+6n=0
a = -288; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-288)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-288}=\frac{-12}{-576} =1/48 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-288}=\frac{0}{-576} =0 $
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