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11/12x-x=-55
We move all terms to the left:
11/12x-x-(-55)=0
Domain of the equation: 12x!=0We add all the numbers together, and all the variables
x!=0/12
x!=0
x∈R
-1x+11/12x+55=0
We multiply all the terms by the denominator
-1x*12x+55*12x+11=0
Wy multiply elements
-12x^2+660x+11=0
a = -12; b = 660; c = +11;
Δ = b2-4ac
Δ = 6602-4·(-12)·11
Δ = 436128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{436128}=\sqrt{16*27258}=\sqrt{16}*\sqrt{27258}=4\sqrt{27258}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(660)-4\sqrt{27258}}{2*-12}=\frac{-660-4\sqrt{27258}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(660)+4\sqrt{27258}}{2*-12}=\frac{-660+4\sqrt{27258}}{-24} $
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