11/2-3y=2/3(-3y+4)

Solution for 11/2-3y=2/3(-3y+4) equation:

11/2-3y=2/3(-3y+4)

We move all terms to the left:

11/2-3y-(2/3(-3y+4))=0


Domain of the equation: 3(-3y+4))!=0

y∈R


We calculate fractions


-3y+()/(-18y)+(33y(-)/(-18y)=0


We calculate terms in parentheses: +(33y(-)/(-18y), so:

33y(-)/(-18y

We add all the numbers together, and all the variables

33y0/(-18y

We multiply all the terms by the denominator


33y0

We add all the numbers together, and all the variables

33y

Back to the equation:

+(33y)


We add all the numbers together, and all the variables

30y+()/(-18y)=0

We multiply all the terms by the denominator


30y*(-18y)+()=0

We add all the numbers together, and all the variables

30y*(-18y)=0

We multiply parentheses

-540y^2=0

a = -540; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-540)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-1080}=0$