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11/2m-26/3m-109/6=86
We move all terms to the left:
11/2m-26/3m-109/6-(86)=0
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
Domain of the equation: 3m!=0determiningTheFunctionDomain 11/2m-26/3m-86-109/6=0
m!=0/3
m!=0
m∈R
We calculate fractions
(-1962m^2)/216m^2+1188m/216m^2+(-1872m)/216m^2-86=0
We multiply all the terms by the denominator
(-1962m^2)+1188m+(-1872m)-86*216m^2=0
Wy multiply elements
(-1962m^2)-18576m^2+1188m+(-1872m)=0
We get rid of parentheses
-1962m^2-18576m^2+1188m-1872m=0
We add all the numbers together, and all the variables
-20538m^2-684m=0
a = -20538; b = -684; c = 0;
Δ = b2-4ac
Δ = -6842-4·(-20538)·0
Δ = 467856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{467856}=684$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-684)-684}{2*-20538}=\frac{0}{-41076} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-684)+684}{2*-20538}=\frac{1368}{-41076} =-38/1141 $
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