11/3+3n=(4/5)n+15

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Solution for 11/3+3n=(4/5)n+15 equation: 



11/3+3n=(4/5)n+15

We move all terms to the left:

11/3+3n-((4/5)n+15)=0



Domain of the equation: 5)n+15)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

3n-((+4/5)n+15)+11/3=0

We calculate fractions


3n+()/5n+15)*3)+55n/5n+15)*3)=0

We calculate fractions


3n+(()*5n)/25n^2+15*3)+55n*5n)/25n^2=0

We multiply all the terms by the denominator


3n*25n^2+(()*5n)+15*3)+55n*5n)=0



We calculate terms in parentheses: +(()*5n), so:

()*5n



Wy multiply elements

75n^3+225n^2+(()*5n)=0



We calculate terms in parentheses: +(()*5n), so:

()*5n



We do not support enpression: n^3

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