11/3x+1=2x-3

Solution for 11/3x+1=2x-3 equation:

11/3x+1=2x-3

We move all terms to the left:

11/3x+1-(2x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

11/3x-2x+3+1=0

We multiply all the terms by the denominator


-2x*3x+3*3x+1*3x+11=0

Wy multiply elements

-6x^2+9x+3x+11=0

We add all the numbers together, and all the variables

-6x^2+12x+11=0

a = -6; b = 12; c = +11;
Δ = b2-4ac
Δ = 122-4·(-6)·11
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{102}}{2*-6}=\frac{-12-2\sqrt{102}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{102}}{2*-6}=\frac{-12+2\sqrt{102}}{-12}
$