11/3x-4=x-6

Solution for 11/3x-4=x-6 equation:

11/3x-4=x-6

We move all terms to the left:

11/3x-4-(x-6)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

11/3x-x+6-4=0

We multiply all the terms by the denominator


-x*3x+6*3x-4*3x+11=0

Wy multiply elements

-3x^2+18x-12x+11=0

We add all the numbers together, and all the variables

-3x^2+6x+11=0

a = -3; b = 6; c = +11;
Δ = b2-4ac
Δ = 62-4·(-3)·11
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{42}}{2*-3}=\frac{-6-2\sqrt{42}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{42}}{2*-3}=\frac{-6+2\sqrt{42}}{-6}
$