11/5(x-20)+6=2/5x-38

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Solution for 11/5(x-20)+6=2/5x-38 equation: 



11/5(x-20)+6=2/5x-38

We move all terms to the left:

11/5(x-20)+6-(2/5x-38)=0



Domain of the equation: 5(x-20)!=0

x∈R





Domain of the equation: 5x-38)!=0

x∈R



We get rid of parentheses

11/5(x-20)-2/5x+38+6=0

We calculate fractions


55x/(25x^2-500x)+(-10xx/(25x^2-500x)+38+6=0

We calculate fractions

We do not support expression: x^3

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