11/5b-5+1/2b=139/10

Solution for 11/5b-5+1/2b=139/10 equation:

11/5b-5+1/2b=139/10

We move all terms to the left:

11/5b-5+1/2b-(139/10)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

11/5b+1/2b-5-(+139/10)=0

We get rid of parentheses

11/5b+1/2b-5-139/10=0

We calculate fractions


(-2780b^2)/100b^2+220b/100b^2+50b/100b^2-5=0

We multiply all the terms by the denominator


(-2780b^2)+220b+50b-5*100b^2=0

We add all the numbers together, and all the variables

(-2780b^2)+270b-5*100b^2=0

Wy multiply elements

(-2780b^2)-500b^2+270b=0

We get rid of parentheses

-2780b^2-500b^2+270b=0

We add all the numbers together, and all the variables

-3280b^2+270b=0

a = -3280; b = 270; c = 0;
Δ = b2-4ac
Δ = 2702-4·(-3280)·0
Δ = 72900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{72900}=270$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(270)-270}{2*-3280}=\frac{-540}{-6560}
=27/328
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(270)+270}{2*-3280}=\frac{0}{-6560}
=0
$