110+(3x+1)=(16x+7)

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Solution for 110+(3x+1)=(16x+7) equation: 



110+(3x+1)=(16x+7)

We move all terms to the left:

110+(3x+1)-((16x+7))=0

We get rid of parentheses

3x-((16x+7))+1+110=0



We calculate terms in parentheses: -((16x+7)), so:

(16x+7)

We get rid of parentheses

16x+7

Back to the equation:

-(16x+7)



We add all the numbers together, and all the variables

3x-(16x+7)+111=0

We get rid of parentheses

3x-16x-7+111=0

We add all the numbers together, and all the variables

-13x+104=0

We move all terms containing x to the left, all other terms to the right

-13x=-104

x=-104/-13

x=+8

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