110-40x2+16=

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Solution for 110-40x2+16= equation: 



110-40x^2+16=

We move all terms to the left:

110-40x^2+16-()=0

We add all the numbers together, and all the variables

-40x^2=0

a = -40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-40)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-80}=0$

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