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11000=(x+20)(x+10)
We move all terms to the left:
11000-((x+20)(x+10))=0
We multiply parentheses ..
-((+x^2+10x+20x+200))+11000=0
We calculate terms in parentheses: -((+x^2+10x+20x+200)), so:We get rid of parentheses
(+x^2+10x+20x+200)
We get rid of parentheses
x^2+10x+20x+200
We add all the numbers together, and all the variables
x^2+30x+200
Back to the equation:
-(x^2+30x+200)
-x^2-30x-200+11000=0
We add all the numbers together, and all the variables
-1x^2-30x+10800=0
a = -1; b = -30; c = +10800;
Δ = b2-4ac
Δ = -302-4·(-1)·10800
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-210}{2*-1}=\frac{-180}{-2} =+90 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+210}{2*-1}=\frac{240}{-2} =-120 $
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