1100=5c2

Solution for 1100=5c2 equation:

1100=5c^2

We move all terms to the left:

1100-(5c^2)=0

a = -5; b = 0; c = +1100;
Δ = b2-4ac
Δ = 02-4·(-5)·1100
Δ = 22000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22000}=\sqrt{400*55}=\sqrt{400}*\sqrt{55}=20\sqrt{55}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{55}}{2*-5}=\frac{0-20\sqrt{55}}{-10}
=-\frac{20\sqrt{55}}{-10}
=-\frac{2\sqrt{55}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{55}}{2*-5}=\frac{0+20\sqrt{55}}{-10}
=\frac{20\sqrt{55}}{-10}
=\frac{2\sqrt{55}}{-1}
$