110=(x/2)(2x+2)

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Solution for 110=(x/2)(2x+2) equation: 


x in (-oo:+oo)

110 = (x/2)*(2*x+2) // - (x/2)*(2*x+2)

110-((x/2)*(2*x+2)) = 0

110-1*1/2*x*(2*x+2) = 0

110-1*1/2*x*(2*x+2) = 0

110-x^2-x = 0

110-x^2-x = 0

110-x^2-x = 0

DELTA = (-1)^2-(-1*4*110)

DELTA = 441

DELTA > 0

x = (441^(1/2)+1)/(-1*2) or x = (1-441^(1/2))/(-1*2)

x = -11 or x = 10

(x+11)*(x-10) = 0

(x+11)*(x-10) = 0

( x+11 )

x+11 = 0 // - 11

x = -11

( x-10 )

x-10 = 0 // + 10

x = 10

x in { -11, 10 }

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