111=3(7b-5)

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Solution for 111=3(7b-5) equation: 



111=3(7b-5)

We move all terms to the left:

111-(3(7b-5))=0



We calculate terms in parentheses: -(3(7b-5)), so:

3(7b-5)

We multiply parentheses

21b-15

Back to the equation:

-(21b-15)



We get rid of parentheses

-21b+15+111=0

We add all the numbers together, and all the variables

-21b+126=0

We move all terms containing b to the left, all other terms to the right

-21b=-126

b=-126/-21

b=+6

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