112+5x=7(3-4x)+20x

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Solution for 112+5x=7(3-4x)+20x equation: 



112+5x=7(3-4x)+20x

We move all terms to the left:

112+5x-(7(3-4x)+20x)=0

We add all the numbers together, and all the variables

5x-(7(-4x+3)+20x)+112=0



We calculate terms in parentheses: -(7(-4x+3)+20x), so:

7(-4x+3)+20x

We add all the numbers together, and all the variables

20x+7(-4x+3)

We multiply parentheses

20x-28x+21

We add all the numbers together, and all the variables

-8x+21

Back to the equation:

-(-8x+21)



We get rid of parentheses

5x+8x-21+112=0

We add all the numbers together, and all the variables

13x+91=0

We move all terms containing x to the left, all other terms to the right

13x=-91

x=-91/13

x=-7

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