112=(13x-8)+(x+20)

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Solution for 112=(13x-8)+(x+20) equation: 



112=(13x-8)+(x+20)

We move all terms to the left:

112-((13x-8)+(x+20))=0



We calculate terms in parentheses: -((13x-8)+(x+20)), so:

(13x-8)+(x+20)

We get rid of parentheses

13x+x-8+20

We add all the numbers together, and all the variables

14x+12

Back to the equation:

-(14x+12)



We get rid of parentheses

-14x-12+112=0

We add all the numbers together, and all the variables

-14x+100=0

We move all terms containing x to the left, all other terms to the right

-14x=-100

x=-100/-14

x=7+1/7

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