112=-7(b-5)-4b

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Solution for 112=-7(b-5)-4b equation: 



112=-7(b-5)-4b

We move all terms to the left:

112-(-7(b-5)-4b)=0



We calculate terms in parentheses: -(-7(b-5)-4b), so:

-7(b-5)-4b

We add all the numbers together, and all the variables

-4b-7(b-5)

We multiply parentheses

-4b-7b+35

We add all the numbers together, and all the variables

-11b+35

Back to the equation:

-(-11b+35)



We get rid of parentheses

11b-35+112=0

We add all the numbers together, and all the variables

11b+77=0

We move all terms containing b to the left, all other terms to the right

11b=-77

b=-77/11

b=-7

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