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112=2/3(w-20
We move all terms to the left:
112-(2/3(w-20)=0
Domain of the equation: 3(w-20)+112!=0We multiply all the terms by the denominator
We move all terms containing w to the left, all other terms to the right
3(w-20)!=-112
w∈R
-(2=0
We add all the numbers together, and all the variables
=0
w=0/1
w=0
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