If it's not what You are looking for type in the equation solver your own equation and let us solve it.
112=2x(2x+6)
We move all terms to the left:
112-(2x(2x+6))=0
We calculate terms in parentheses: -(2x(2x+6)), so:We get rid of parentheses
2x(2x+6)
We multiply parentheses
4x^2+12x
Back to the equation:
-(4x^2+12x)
-4x^2-12x+112=0
a = -4; b = -12; c = +112;
Δ = b2-4ac
Δ = -122-4·(-4)·112
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-44}{2*-4}=\frac{-32}{-8} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+44}{2*-4}=\frac{56}{-8} =-7 $
| x/6-2x-8/4=3x-3 | | -2p=11/4 | | 7*4=3x | | 20-4x=10-9(4-x)-(3x-6) | | 7*3=3x | | 6=4-k/3 | | 1/3x-2=19 | | 1/8x+7=15 | | x-(-34)=-17 | | 5d=21+4d | | -10x-20=130 | | 10x+25-6x=30+4x | | 8y-10=90 | | 2(2-X)+5=3-5x | | 10x-4+8x+3=91 | | 3(x-4)+(2x+8)=4x+4 | | 19=2n-1 | | 9+3a=21 | | 5-3(x+2)=13 | | 4x-8=42+5 | | −3/1=4/j−3/10 | | 13x^2+13x=10 | | 0=22-16t^2 | | 2(5c-2)-2c=3(2c+3)+7 | | 18x^2+17x−15=(2x+3)*(9x-5) | | 2=6-22(x+6) | | x+2/3+x+3/2=2 | | 0=x^2+5x+0 | | 4t+6t+3=-2t | | x+4/3+x+3/4=2 | | 5x=4(-9)+8 | | -35=7/5u |