112=4(6+n)+7n

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Solution for 112=4(6+n)+7n equation: 



112=4(6+n)+7n

We move all terms to the left:

112-(4(6+n)+7n)=0

We add all the numbers together, and all the variables

-(4(n+6)+7n)+112=0



We calculate terms in parentheses: -(4(n+6)+7n), so:

4(n+6)+7n

We add all the numbers together, and all the variables

7n+4(n+6)

We multiply parentheses

7n+4n+24

We add all the numbers together, and all the variables

11n+24

Back to the equation:

-(11n+24)



We get rid of parentheses

-11n-24+112=0

We add all the numbers together, and all the variables

-11n+88=0

We move all terms containing n to the left, all other terms to the right

-11n=-88

n=-88/-11

n=+8

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