112=4(7+3b)

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Solution for 112=4(7+3b) equation: 



112=4(7+3b)

We move all terms to the left:

112-(4(7+3b))=0

We add all the numbers together, and all the variables

-(4(3b+7))+112=0



We calculate terms in parentheses: -(4(3b+7)), so:

4(3b+7)

We multiply parentheses

12b+28

Back to the equation:

-(12b+28)



We get rid of parentheses

-12b-28+112=0

We add all the numbers together, and all the variables

-12b+84=0

We move all terms containing b to the left, all other terms to the right

-12b=-84

b=-84/-12

b=+7

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