113x-4+2x-190.7(x-5)+0.5=1-0.3(10-2x)-0.5

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Solution for 113x-4+2x-190.7(x-5)+0.5=1-0.3(10-2x)-0.5 equation: 



113x-4+2x-190.7(x-5)+0.5=1-0.3(10-2x)-0.5

We move all terms to the left:

113x-4+2x-190.7(x-5)+0.5-(1-0.3(10-2x)-0.5)=0

We add all the numbers together, and all the variables

113x+2x-190.7(x-5)-(1-0.3(-2x+10)-0.5)-4+0.5=0

We add all the numbers together, and all the variables

115x-190.7(x-5)-(1-0.3(-2x+10)-0.5)-3.5=0

We multiply parentheses

115x-190.7x-(1-0.3(-2x+10)-0.5)+953.5-3.5=0



We calculate terms in parentheses: -(1-0.3(-2x+10)-0.5), so:

1-0.3(-2x+10)-0.5

determiningTheFunctionDomain
-0.3(-2x+10)+1-0.5

We add all the numbers together, and all the variables

-0.3(-2x+10)+0.5

We multiply parentheses

0.6x-3+0.5

We add all the numbers together, and all the variables

0.6x-2.5

Back to the equation:

-(0.6x-2.5)



We add all the numbers together, and all the variables

-75.7x-(0.6x-2.5)+950=0

We get rid of parentheses

-75.7x-0.6x+2.5+950=0

We add all the numbers together, and all the variables

-76.3x+952.5=0

We move all terms containing x to the left, all other terms to the right

-76.3x=-952.5

x=-952.5/-76.3

x=12+7.5306122448978/15.571428571428

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