114(z+3)=14z+21

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Solution for 114(z+3)=14z+21 equation: 



114(z+3)=14z+21

We move all terms to the left:

114(z+3)-(14z+21)=0

We multiply parentheses

114z-(14z+21)+342=0

We get rid of parentheses

114z-14z-21+342=0

We add all the numbers together, and all the variables

100z+321=0

We move all terms containing z to the left, all other terms to the right

100z=-321

z=-321/100

z=-3+21/100

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