114+(2y-4)=(7y-15)

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Solution for 114+(2y-4)=(7y-15) equation: 



114+(2y-4)=(7y-15)

We move all terms to the left:

114+(2y-4)-((7y-15))=0

We get rid of parentheses

2y-((7y-15))-4+114=0



We calculate terms in parentheses: -((7y-15)), so:

(7y-15)

We get rid of parentheses

7y-15

Back to the equation:

-(7y-15)



We add all the numbers together, and all the variables

2y-(7y-15)+110=0

We get rid of parentheses

2y-7y+15+110=0

We add all the numbers together, and all the variables

-5y+125=0

We move all terms containing y to the left, all other terms to the right

-5y=-125

y=-125/-5

y=+25

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