116=(5z-29)

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Solution for 116=(5z-29) equation: 



116=(5z-29)

We move all terms to the left:

116-((5z-29))=0



We calculate terms in parentheses: -((5z-29)), so:

(5z-29)

We get rid of parentheses

5z-29

Back to the equation:

-(5z-29)



We get rid of parentheses

-5z+29+116=0

We add all the numbers together, and all the variables

-5z+145=0

We move all terms containing z to the left, all other terms to the right

-5z=-145

z=-145/-5

z=+29

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