116=4(1+4x)

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Solution for 116=4(1+4x) equation: 



116=4(1+4x)

We move all terms to the left:

116-(4(1+4x))=0

We add all the numbers together, and all the variables

-(4(4x+1))+116=0



We calculate terms in parentheses: -(4(4x+1)), so:

4(4x+1)

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

-16x-4+116=0

We add all the numbers together, and all the variables

-16x+112=0

We move all terms containing x to the left, all other terms to the right

-16x=-112

x=-112/-16

x=+7

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