116=4x-5(4x-4)

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Solution for 116=4x-5(4x-4) equation: 



116=4x-5(4x-4)

We move all terms to the left:

116-(4x-5(4x-4))=0



We calculate terms in parentheses: -(4x-5(4x-4)), so:

4x-5(4x-4)

We multiply parentheses

4x-20x+20

We add all the numbers together, and all the variables

-16x+20

Back to the equation:

-(-16x+20)



We get rid of parentheses

16x-20+116=0

We add all the numbers together, and all the variables

16x+96=0

We move all terms containing x to the left, all other terms to the right

16x=-96

x=-96/16

x=-6

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