117-4(x+3)-5=11+2(4-2x)-16

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Solution for 117-4(x+3)-5=11+2(4-2x)-16 equation: 


Simplifying
117 + -4(x + 3) + -5 = 11 + 2(4 + -2x) + -16

Reorder the terms:
117 + -4(3 + x) + -5 = 11 + 2(4 + -2x) + -16
117 + (3 * -4 + x * -4) + -5 = 11 + 2(4 + -2x) + -16
117 + (-12 + -4x) + -5 = 11 + 2(4 + -2x) + -16

Reorder the terms:
117 + -12 + -5 + -4x = 11 + 2(4 + -2x) + -16

Combine like terms: 117 + -12 = 105
105 + -5 + -4x = 11 + 2(4 + -2x) + -16

Combine like terms: 105 + -5 = 100
100 + -4x = 11 + 2(4 + -2x) + -16
100 + -4x = 11 + (4 * 2 + -2x * 2) + -16
100 + -4x = 11 + (8 + -4x) + -16

Reorder the terms:
100 + -4x = 11 + 8 + -16 + -4x

Combine like terms: 11 + 8 = 19
100 + -4x = 19 + -16 + -4x

Combine like terms: 19 + -16 = 3
100 + -4x = 3 + -4x

Add '4x' to each side of the equation.
100 + -4x + 4x = 3 + -4x + 4x

Combine like terms: -4x + 4x = 0
100 + 0 = 3 + -4x + 4x
100 = 3 + -4x + 4x

Combine like terms: -4x + 4x = 0
100 = 3 + 0
100 = 3

Solving
100 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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