117=(1/2)h(10+3)

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Solution for 117=(1/2)h(10+3) equation: 



117=(1/2)h(10+3)

We move all terms to the left:

117-((1/2)h(10+3))=0



Domain of the equation: 2)h(10+3))!=0

h∈R



We add all the numbers together, and all the variables

-((+1/2)h13)+117=0

We multiply all the terms by the denominator


-((+1+117*2)h13)=0



We calculate terms in parentheses: -((+1+117*2)h13), so:

(+1+117*2)h13

We add all the numbers together, and all the variables

235h13

We add all the numbers together, and all the variables

235h^13

We do not support ehpression: h^13

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