117=(1/2)h(10+3)

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Solution for 117=(1/2)h(10+3) equation:



117=(1/2)h(10+3)
We move all terms to the left:
117-((1/2)h(10+3))=0
Domain of the equation: 2)h(10+3))!=0
h∈R
We add all the numbers together, and all the variables
-((+1/2)h13)+117=0
We multiply all the terms by the denominator
-((+1+117*2)h13)=0
We calculate terms in parentheses: -((+1+117*2)h13), so:
(+1+117*2)h13
We add all the numbers together, and all the variables
235h13
We add all the numbers together, and all the variables
235h^13
We do not support ehpression: h^13

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