117=3(p-5)+8

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Solution for 117=3(p-5)+8 equation: 



117=3(p-5)+8

We move all terms to the left:

117-(3(p-5)+8)=0



We calculate terms in parentheses: -(3(p-5)+8), so:

3(p-5)+8

We multiply parentheses

3p-15+8

We add all the numbers together, and all the variables

3p-7

Back to the equation:

-(3p-7)



We get rid of parentheses

-3p+7+117=0

We add all the numbers together, and all the variables

-3p+124=0

We move all terms containing p to the left, all other terms to the right

-3p=-124

p=-124/-3

p=41+1/3

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