117=3+2(8b-7)

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Solution for 117=3+2(8b-7) equation:



117=3+2(8b-7)
We move all terms to the left:
117-(3+2(8b-7))=0
We calculate terms in parentheses: -(3+2(8b-7)), so:
3+2(8b-7)
determiningTheFunctionDomain 2(8b-7)+3
We multiply parentheses
16b-14+3
We add all the numbers together, and all the variables
16b-11
Back to the equation:
-(16b-11)
We get rid of parentheses
-16b+11+117=0
We add all the numbers together, and all the variables
-16b+128=0
We move all terms containing b to the left, all other terms to the right
-16b=-128
b=-128/-16
b=+8

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