117=9(3+n)

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Solution for 117=9(3+n) equation: 



117=9(3+n)

We move all terms to the left:

117-(9(3+n))=0

We add all the numbers together, and all the variables

-(9(n+3))+117=0



We calculate terms in parentheses: -(9(n+3)), so:

9(n+3)

We multiply parentheses

9n+27

Back to the equation:

-(9n+27)



We get rid of parentheses

-9n-27+117=0

We add all the numbers together, and all the variables

-9n+90=0

We move all terms containing n to the left, all other terms to the right

-9n=-90

n=-90/-9

n=+10

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