117y+156=(9y+12)

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Solution for 117y+156=(9y+12) equation: 



117y+156=(9y+12)

We move all terms to the left:

117y+156-((9y+12))=0



We calculate terms in parentheses: -((9y+12)), so:

(9y+12)

We get rid of parentheses

9y+12

Back to the equation:

-(9y+12)



We get rid of parentheses

117y-9y-12+156=0

We add all the numbers together, and all the variables

108y+144=0

We move all terms containing y to the left, all other terms to the right

108y=-144

y=-144/108

y=-1+1/3

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