118=-4(1-5b)+2

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Solution for 118=-4(1-5b)+2 equation: 



118=-4(1-5b)+2

We move all terms to the left:

118-(-4(1-5b)+2)=0

We add all the numbers together, and all the variables

-(-4(-5b+1)+2)+118=0



We calculate terms in parentheses: -(-4(-5b+1)+2), so:

-4(-5b+1)+2

We multiply parentheses

20b-4+2

We add all the numbers together, and all the variables

20b-2

Back to the equation:

-(20b-2)



We get rid of parentheses

-20b+2+118=0

We add all the numbers together, and all the variables

-20b+120=0

We move all terms containing b to the left, all other terms to the right

-20b=-120

b=-120/-20

b=+6

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