118=6x+2(4x+10)

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Solution for 118=6x+2(4x+10) equation: 



118=6x+2(4x+10)

We move all terms to the left:

118-(6x+2(4x+10))=0



We calculate terms in parentheses: -(6x+2(4x+10)), so:

6x+2(4x+10)

We multiply parentheses

6x+8x+20

We add all the numbers together, and all the variables

14x+20

Back to the equation:

-(14x+20)



We get rid of parentheses

-14x-20+118=0

We add all the numbers together, and all the variables

-14x+98=0

We move all terms containing x to the left, all other terms to the right

-14x=-98

x=-98/-14

x=+7

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