1196=(2x-6)x

Solution for 1196=(2x-6)x equation:

1196=(2x-6)x

We move all terms to the left:

1196-((2x-6)x)=0


We calculate terms in parentheses: -((2x-6)x), so:

(2x-6)x

We multiply parentheses

2x^2-6x

Back to the equation:

-(2x^2-6x)


We get rid of parentheses

-2x^2+6x+1196=0

a = -2; b = 6; c = +1196;
Δ = b2-4ac
Δ = 62-4·(-2)·1196
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-98}{2*-2}=\frac{-104}{-4}
=+26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+98}{2*-2}=\frac{92}{-4}
=-23
$