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119=5x(x+4)
We move all terms to the left:
119-(5x(x+4))=0
We calculate terms in parentheses: -(5x(x+4)), so:We get rid of parentheses
5x(x+4)
We multiply parentheses
5x^2+20x
Back to the equation:
-(5x^2+20x)
-5x^2-20x+119=0
a = -5; b = -20; c = +119;
Δ = b2-4ac
Δ = -202-4·(-5)·119
Δ = 2780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2780}=\sqrt{4*695}=\sqrt{4}*\sqrt{695}=2\sqrt{695}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{695}}{2*-5}=\frac{20-2\sqrt{695}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{695}}{2*-5}=\frac{20+2\sqrt{695}}{-10} $
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