11=(k+3)/9.1

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Solution for 11=(k+3)/9.1 equation: 



11=(k+3)/9.1

We move all terms to the left:

11-((k+3)/9.1)=0

We multiply all the terms by the denominator


-((k+3)+11*9.1)=0



We calculate terms in parentheses: -((k+3)+11*9.1), so:

(k+3)+11*9.1

We add all the numbers together, and all the variables

(k+3)+100.1

We get rid of parentheses

k+3+100.1

We add all the numbers together, and all the variables

k+103.1

Back to the equation:

-(k+103.1)



We get rid of parentheses

-k-103.1=0

We add all the numbers together, and all the variables

-1k-103.1=0

We move all terms containing k to the left, all other terms to the right

-k=103.1

k=103.1/-1

k=-103+0.099999999999994/1

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