11=(y-3)-8y

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Solution for 11=(y-3)-8y equation: 



11=(y-3)-8y

We move all terms to the left:

11-((y-3)-8y)=0



We calculate terms in parentheses: -((y-3)-8y), so:

(y-3)-8y

We add all the numbers together, and all the variables

-8y+(y-3)

We get rid of parentheses

-8y+y-3

We add all the numbers together, and all the variables

-7y-3

Back to the equation:

-(-7y-3)



We get rid of parentheses

7y+3+11=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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