11=-3(2y-2)-7

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Solution for 11=-3(2y-2)-7 equation: 



11=-3(2y-2)-7

We move all terms to the left:

11-(-3(2y-2)-7)=0



We calculate terms in parentheses: -(-3(2y-2)-7), so:

-3(2y-2)-7

We multiply parentheses

-6y+6-7

We add all the numbers together, and all the variables

-6y-1

Back to the equation:

-(-6y-1)



We get rid of parentheses

6y+1+11=0

We add all the numbers together, and all the variables

6y+12=0

We move all terms containing y to the left, all other terms to the right

6y=-12

y=-12/6

y=-2

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