11=-8(x+4)+3(5-2x)

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Solution for 11=-8(x+4)+3(5-2x) equation:



11=-8(x+4)+3(5-2x)
We move all terms to the left:
11-(-8(x+4)+3(5-2x))=0
We add all the numbers together, and all the variables
-(-8(x+4)+3(-2x+5))+11=0
We calculate terms in parentheses: -(-8(x+4)+3(-2x+5)), so:
-8(x+4)+3(-2x+5)
We multiply parentheses
-8x-6x-32+15
We add all the numbers together, and all the variables
-14x-17
Back to the equation:
-(-14x-17)
We get rid of parentheses
14x+17+11=0
We add all the numbers together, and all the variables
14x+28=0
We move all terms containing x to the left, all other terms to the right
14x=-28
x=-28/14
x=-2

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