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11=1/3(10z+15)
We move all terms to the left:
11-(1/3(10z+15))=0
Domain of the equation: 3(10z+15))!=0We multiply all the terms by the denominator
z∈R
-(1+11*3(10z+15))=0
We calculate terms in parentheses: -(1+11*3(10z+15)), so:We add all the numbers together, and all the variables
1+11*3(10z+15)
determiningTheFunctionDomain 11*3(10z+15)+1
Wy multiply elements
33z(1+1
Back to the equation:
-(33z(1+1)
-(33z2=0
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