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11=1/3(3x-12)
We move all terms to the left:
11-(1/3(3x-12))=0
Domain of the equation: 3(3x-12))!=0We multiply all the terms by the denominator
x∈R
-(1+11*3(3x-12))=0
We calculate terms in parentheses: -(1+11*3(3x-12)), so:We add all the numbers together, and all the variables
1+11*3(3x-12)
determiningTheFunctionDomain 11*3(3x-12)+1
Wy multiply elements
33x(3+1
Back to the equation:
-(33x(3+1)
-(33x4=0
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