11=2(k+-1)+-3

Solution for 11=2(k+-1)+-3 equation:

11=2(k+-1)+-3

We move all terms to the left:

11-(2(k+-1)+-3)=0

We add all the numbers together, and all the variables

-(2(k-1)+-3)+11=0

We use the square of the difference formula

-(2(k-1)-3)+11=0


We calculate terms in parentheses: -(2(k-1)-3), so:

2(k-1)-3

We multiply parentheses

2k-2-3

We add all the numbers together, and all the variables

2k-5

Back to the equation:

-(2k-5)


We get rid of parentheses

-2k+5+11=0

We add all the numbers together, and all the variables

-2k+16=0

We move all terms containing k to the left, all other terms to the right

-2k=-16

k=-16/-2

k=+8